All girls must weight different, otherwise there would be repetition in pair weights. Let weights be a>b>c>d>e. Then largest weight must be a+b, then a+c. Lightest must be e+d, and then e+c. Sum of all the pair wise weights is 4(a+b+c+d+e) = 1212, and hence (a+b+c+d+e) = 303. Now c = (a+b+c+d+e)- (a+b) - (d+e) = 1212 - 129 - 114 = 60. a+c = 125, and hence a = 65, and a+b = 129, so b = 64. Similarly the rest.